Lising Session on a group

Disabled

Published 7 years ago

Hello,

We have a group tree of sessions/other groups and I would like to list session without sub entries:

Example:

\
\Client

\Client\session1
\Client\session2
\Client\subgroup1
\Client\subgroup1\session3
\Client\subgroup1\session4
\Client\subgroup2\session5
If I use

Get-RDMSession -GroupName Clients

it's only returning Client object

If I use :
Get-RDMSession -GroupName Clients -IncludeSubFolders

It's returning all session, even those on sub groups

I would lile to get a list which is returniong only "sesson1, session2, subgorup1, subgroup2"

Thanks in advance for Help

Antoine

All Comments (1)

David Grandolfo

Published 7 years ago

Hello,

Could you try these scripts if they solve your need?

This script returns the entries including the parent folder
$group = 'myfoldername'
Get-RDMSession | Where-Object {$_.Group -eq $group -or ($_.ConnectionType -eq 'Group' -and $_.Group -eq ($group + "\" + $_.Name))}

Or this one without the parent folder
$group = 'myfoldername'
Get-RDMSession | Where-Object {($_.ConnectionType -ne 'Group' -and $_.Group -eq $group) -or ($_.ConnectionType -eq 'Group' -and $_.Group -eq ($group + "\" + $_.Name))}
Best regards,

David Grandolfo